# Hearts

I saw this before on Reddit where the contour plot of a sixth degree equation renders the shape of a 3-dimensional heart. In the spirit of valentines day, I’ll post it here.

$(x^2+\frac{9y^2}{4}+z^2-1)^3-x^2z^3-\frac{9y^2z^3}{80}=0$

Here’s some pics:

Happy valentines and Chinese new year! 😀

## One thought on “Hearts”

1. frank says:

Pretty interesting.